if(weight < items[curr].first) return dp[curr][weight] = knapsack01(dp, items, curr-1, weight, profit); return dp[curr][weight] = max(items[curr].second + knapsack01 ...
DAA-Knapsack-problem-using-branch-and-bound-strategy. Write a program to solve a 0-1 Knapsack problem using dynamic programming or branch and bound strategy.
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