If GCD(a,b) = 1, then for any remainder ra modulo a and any remainder rb modulo b there exists integer n, such that n = ra (mod a) and n = ra(mod b). If n1 and n2 are ...

division_with_remainder = 12 // 5 # should be 2.4 print(division_with_remainder) # prints 2 # 5 goes into 12 two times. (5 * 2 is 10). The remainder is 2. # Getting ...